[Tutorial]Cara bikin lambang apple

[ShiNicHi23]

zzz. . . ini dari 2 taon yg lalu gw jga uda tau. . . -_-"

[Alter_Ego]

zzz. . . ini dari 2 taon yg lalu gw jga uda tau. . . -_-"

(ಠ_ಠ)??

[BecKaX]

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[Saladin]

Misal: x=18
5x=90
3x+2x=90
2x=90-3x
sin2x=sin⁡(90-3x)
sin2x=cos3x
2 sinx cosx=〖4cos〗^3 x-3cosx
2sinx=〖4cos〗^2 x-3
2sinx=4(1-〖sin〗^2 x)-3
〖4sin〗^2 x+2sinx-1=0
sinx=(-2±√(2^2-4 .4 .(-1) ))/(2 .2)
sinx=(-2+2√5)/4
sin18= (√5-1)/4
cos36=1-〖2sin〗^2 18=1-2 ((5-2√5+1))/16=4/4-(3-√5)/4
cos⁡36=(√5+1)/4

jadi kangen ngitung
libur kelamaan nih

[wadezig]

Kok gk isa y... Cuma msukin yg kyk iee kan?

ieenya di copy, trus pastenya di warcraft om

[bluedarknezz]

Misal: x=18
5x=90
3x+2x=90
2x=90-3x
sin2x=sin⁡(90-3x)
sin2x=cos3x
2 sinx cosx=〖4cos〗^3 x-3cosx
2sinx=〖4cos〗^2 x-3
2sinx=4(1-〖sin〗^2 x)-3
〖4sin〗^2 x+2sinx-1=0
sinx=(-2±√(2^2-4 .4 .(-1) ))/(2 .2)
sinx=(-2+2√5)/4
sin18= (√5-1)/4
cos36=1-〖2sin〗^2 18=1-2 ((5-2√5+1))/16=4/4-(3-√5)/4
cos⁡36=(√5+1)/4

(x-x)x = x² - x² = 0
x² - x² = (x-x)(x+x)
(x-x)x = (x-x)(x+x)
kedua ruas dibagi x-x
x = x+x

1 = 2

[Crazy_Bomb]

sep deh..

[wadezig]

up up, tadi di channel Indogamers masih ada yg nanyain, ayo2 bagi2 info

[fazameonk]

penting ya gan

[Luckybringer]

Misal: x=18
5x=90
3x+2x=90
2x=90-3x
sin2x=sin⁡(90-3x)
sin2x=cos3x
2 sinx cosx=〖4cos〗^3 x-3cosx
2sinx=〖4cos〗^2 x-3
2sinx=4(1-〖sin〗^2 x)-3
〖4sin〗^2 x+2sinx-1=0
sinx=(-2±√(2^2-4 .4 .(-1) ))/(2 .2)
sinx=(-2+2√5)/4
sin18= (√5-1)/4
cos36=1-〖2sin〗^2 18=1-2 ((5-2√5+1))/16=4/4-(3-√5)/4
cos⁡36=(√5+1)/4

[[R]A[R]E[L]Y]

wah tq kk.brb pamer hhha

[[R]A[R]E[L]Y]

kwkkwkw pada nyoba nih yeee

[wadezig]

penting ya gan

bodo yeee

[detective007]

(x-x)x = x² - x² = 0
x² - x² = (x-x)(x+x)
(x-x)x = (x-x)(x+x)
kedua ruas dibagi x-x
x = x+x

1 = 2

Yang di bold nge bug...

=(x-x)(x+x)

=x² + x² - x² - x²

=0

[Ch41n_L19htn1n9]

it's true, itu valid koq, x2 - x2 juga 0